One mole of an ideal gas at 900 K, undergoes two reversible processes, I followed by II, as shown below.
If the work done by the gas in the two process are same, the value of In 
___
(U: internal energy, S: entropy, p: pressure, V: volume, R: gas constant)
(Given: molar heat capacity at constant volume, C v,m of the gas is 
R)
Text Solution
Verified by Experts10
(10)
1 st process is adiabatic since entropy is constant.
= 450R - 2250R = -1800R
W 1 =-1800R ...(1)
In 2 nd process internal energy is constant it means it is a isothermal process.
W 2 =-2.303nRTlog 
....(2)
....(3)
Given, n = 1 mole, here temperature is unknown
U = nC v T for process II
450R = 1x 
RT
T= 
= 180K
Equation (1) = equation (2)
W 1 =W 2
-1800R = -1xRxl80ln 
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